# Precision problem? (Program Bug and Problems)

I have come out with this problem:
for t=0 to 10 step 0.01
if t=int(t) then print t
next t
Does not print integer numbers (1 to 10)

I've tried several ways (using auxiliary variables) but none seem to 'compare' properly the 'float' variable and the 'integer' variable.

Joan

## Precision problem?

The error you got in the condition "IF":

If you want to see the condition integers "IF" is not necessary.

Basic-256, has very good accuracy, works fast and well.

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for t = 0 to 10 step 0.01

print INT (t) #<<<<< Así, si funciona!!!

next t
END

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## Precision problem?

Also, as you start the interval to "0.01", the sequence is correct, as we see in the series.!

Is not "1.00", for which the sequence is "0.01"

Basic-256, is perfect!

The zeros "0" to the right, not written!

:::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
0 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.1 0.11 0.12 0.13 0.14 0.15 0.16 0.17 0.18 0.19 0.2 0.21 0.22 0.23 0.24 0.25 0.26 0.27 0.28 0.29 0.3 0.31 0.32 0.33 0.34 0.35 0.36 0.37 0.38 0.39 0.4 0.41 0.42 0.43 0.44 0.45 0.46 0.47 0.48 0.49 0.5 0.51 0.52 0.53 0.54 0.55 0.56 0.57 0.58 0.59 0.6 0.61 0.62 0.63 0.64 0.65 0.66 0.67 0.68 0.69 0.7 0.71 0.72 0.73 0.74 0.75 0.76 0.77 0.78 0.79 0.8 0.81 0.82 0.83 0.84 0.85 0.86 0.87 0.88 0.89 0.9 0.91 0.92 0.93 0.94 0.95 0.96 0.97 0.98 >>> "0.99 1 1.01 <<<< " 1.02 1.03 1.04 1.05 1.06 1.07 1.08 1.09 1.1 1.11 1.12 1.13 1.14 1.15 1.16 1.17 1.18 1.19 1.2 1.21 1.22 1.23 1.24 1.25 1.26 1.27 1.28 1.29 1.3 1.31 1.32 1.33 1.34 1.35 1.36 1.37 1.38 1.39 1.4 1.41 1.42 1.43 1.44 1.45 1.46 1.47 1.48 1.49 1.5 1.51 1.52 1.53 1.54 1.55 1.56 1.57 1.58 1.59 1.6 1.61 1.62 1.63 1.64 1.65 1.66 1.67 1.68 1.69 1.7 1.71 1.72 1.73 1.74 1.75 1.76 1.77 1.78 1.79 1.8 1.81 1.82 1.83 1.84 1.85 1.86 1.87 1.88 1.89 1.9 1.91 1.92 1.93 1.94 1.95 1.96 1.97 1.98 1.99

## Precision problem?

Other solution:

cls
for t = 0 to 10 step 0.01
if instr (string (t),".") = 0 then print t #transform number to string !!!!
next t
end

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0
1
2
3
4
5
6
7
8
9
10

## Precision problem?

OMG. I am working on a fix/work around in the code. I will have something soon.

Jim

## Precision problem?

I have come out with this problem:
for t=0 to 10 step 0.01
if t=int(t) then print t
next t
Does not print integer numbers (1 to 10)

I've tried several ways (using auxiliary variables) but none seem to 'compare' properly the 'float' variable and the 'integer' variable.