Under UBUNTU/LINUX the code works just as you like it. As an old programmer I do not trust the modulo operator if either side is a floating point. :) I guess there could be a rounding or floating point problem.

I would implement this as a string of digits so there would be no way of getting all "floaty" on us.

# wcheck = 44444444

# wcheck$ = string(wcheck) # different variable - same name almost but a string

# or

wcheck$ = "21312312312345342341234324"

dcsum = 0

for i = 1 to length(wcheck$)

dcsum = dcsum + int(mid(wcheck$,i,1))

next i

print dcsum

On the same note, here's a bit of an anomaly I've discovered. When I run this bit of code:

wcheck = 11148470

t = float(wcheck)/10^8

dcsum = 0

for ddi = 1 to 7

t=float(t*10)

dcsum = dcsum + t%10

t = t-(t%10)

if t>0 then

next ddi

endif

print dcsum

it treats the 4 as a 3. So if wcheck = 44444444, it gives me a 31 instead of 32. It does the same thing if I use a 3 in the fourth position, it treats it as a 2. All other digits are okay. Any idea why this is happening? I've run it on WinNT, XP & 7 with the same result.

]]>dim d(10)

for i=1 to 10

d[i-1] = i

next i

wcheck = 11148470

t = float(wcheck)/10^8

dcsum = 0

for ddi = 1 to 7

t=float(t*10)

dcsum = dcsum + t%10

t = t-(t%10)

if t>0 then

next ddi

endif

print dcsum

Thanks for heading me in the right direction! I'd still like to find a way to use variable values as part of another variable though, like this:

for i=1 to 10

d(i) = i

next i

The end result I want is

d1 = 1

d2 = 2

etc.

Any way to do this?

]]>wcheck = ????

t = wcheck

dcsum = 0

for ddi = 1 to 10

dcsum = t mod 10

t = dcsum \ 10

next ddi

for ddi=1 to 10

dc(ddi)$=mid(string(wcheck),ddi,1)

dcsum=dcsum+int(dc(ddi)$)

next ddi

What I'm trying to do is take a ten-digit number (wcheck) and add the digits together to check against a checksum. Is there a way to make the value of ddi part of another variable (dc1$-dc10$)? Or is there an easier way of doing this rather than converting the number to a string, stripping the numbers with the mid statement, then converting them back to add them?

Thanks!

]]>