Find the position within an array larger than 3D (New Features)

by lrcvs, Saturday, May 05, 2012, 08:39 (1786 days ago) @ Jim

I understand means well.

But I do not understand is the concept of fourth, fifth, sixth, .... dimension.

For example: Z = [5 4 3 2]

mathematically speaking it would be 5 * 4 * 3 * 2 = 120 elements.

But 5 * 4 = X * Y = level 1 = 20 elements in each level.

20 * 3 = 20 * Z is the number of 3D or level 3 = 60 items.

So far, so good.

Now we have the 4D = 2.

I understand that at level 3, the last layer, and each element has an extension of 2 more items of the fourth dimension.

So I think and say 20 elements of the last level * 2 extensions more = 40 elements.

I still think if 3D = 60 items + 40 items in the fouth dimension = 100 items.

No item that is the 120 mathematically speaking.

What is your concept of the following dimensions to 3D?

(the fourth, fifth, sixth ... dimension)


Complete thread:

 RSS Feed of thread

powered by my little forum